How do you do this question?
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Answer:
Divergent
Step-by-step explanation:
an = 3 sin(2/n)
Choose bn = 3 (2/n).
Using Limit Comparison Test:
lim(n→∞) an / bn
= lim(n→∞) [3 sin(2/n)] / [3 (2/n)]
= lim(n→∞) [sin(2/n)] / (2/n)
= 1
The limit is greater than 0, and bn diverges, so an also diverges.