Find two numbers if their ratio is 9:11 and their difference is 6.
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Answer:
Step-by-step explanation:
27,33
9*3 is 27
11*3 is 33
33-27 is 6
i only have one, sorry!
Answer:
Step-by-step explanation:
Let the larger number = y
Let the smaller number = x
x/y = 9/11
y - x = 6
Add x to both sides of the second equation
y = 6 + x
Substitute into the first equation
x/(x + 6) = 9/11
Cross multiply
11x = 9(x + 6)
Remove the brackets
11x = 9x + 54
Subtract 9x from both sides.
2x = 54
x = 54/2
x = 27
y = 27 + 6
y = 33
(27,33)
The way I've done it, there isn't a second pair.
I suppose you could do it this way.
9/11 = -27/-33
-27 - - 33 = 6
So the second pair could be
(-27, - 33)