Find the equation of the line that is parallel to the given line and passes through the given point. y=-5x+7;(7,0)
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Answer:
y = -5x + 35.
Step-by-step explanation:
y = -5x + 7
The slope for that y = -5x+7 is -5. Parallel lines have the same slopes which means the line parallel to that one will also have a slope of -5.
So now let's use the slope intercept form to create the equation that is parallel to the above equation.
y = mx + b
Since slope (m) is -5, we can plug it into the equation.
y = -5x + b
Now let's use the point (7,0) to find the y-intercept (b). We can do that by plugging the numbers in (7 for x and 0 for y).
y = -5x + b
0 = -5(7) + b
0 = -35 + b
b = 35
Now let's plug the y-intercept back into the equation.
y = -5x + 35
Therefore, the equation is y = -5x + 35.
Hope this helped! If not, please let me know! <3