One particle has a charge of 4.2 x 10-°C, while another particle has a charge
of 1.10 10-9 C. If the two particles are separated by 0.005 m, what is the
electromagnetic force between them? The equation for Coulomb's law is
F = kongs, and the constant, k, equals 9.00 x 10°Nm2/C2

One particle has a charge of 42 x 10C while another particle has a charge of 110 109 C If the two particles are separated by 0005 m what is the electromagnetic class=

Respuesta :

The formula is F = 9x10^9 x q1 x q2 / r^2

Force = 9x10^9 x (4.2x10-9 x 1.1 x 10^-9) / 0.005^2

I hope you can do the maths on your calculator? Else ask me &!I will help.

Answer:

1.66*10^-3N

Explanation:

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