Question

In a chemistry class, 12 L of a 12% alcohol solution must be mixed with a 20% solution to get a 14% solution. How many liters of the 20% solution are needed?

Answer 1

Let x = liters 20% solution to be added
then

.12(12) + .20x = .14(12+x)
.12(12) + .20x = .14(12+x)
1.44 + .20x = 1.68 + .14x
.20x = .24 + .14x
.06x = .24
x = 4 liters


Hope this helped!!

Answer 2

4 liters of 20% solution are needed to get a 14% solution.

Suppose x liters of 20% solution is needed to get a 14% solution.

What is a solution?

The solution is a homogenous mixture of two or more substances in relative amounts.

So, according to the question

Final concentration of solution = 14%

So, 12% of 12  + 20% of x = 14% of (12+x)

12*12/100 + 20*x/100 = 14*(12+x)/100

144 + 20x = 168 + 14x

6x =24

x=4

4 liters of 20% solution is needed to get a 14% solution.

Therefore, 4 liters of 20% solution is needed to get a 14% solution.

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