Answer:
x = [tex]\sqrt{53}[/tex]
Step-by-step explanation:
Using Pythagoras' identity on the upper right triangle.
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides.
Let the third side be d, then
d² + b² = a² , that is
d² + 8² = 11²
d² + 64 = 121 ( subtract 64 from both sides )
d² = 57
Using Pythagoras' identity on the lower right triangle, then
x² + c² = d²
x² + 2² = 57
x² + 4 = 57 ( subtract 4 from both sides )
x² = 53 ( take the square root of both sides )
x = [tex]\sqrt{53}[/tex]
