Question

Find the distance between the two points in simplest radical form.
n.
(6, -9) and (1,3)
Help?

Answer 1

$\large\underline{\underline{\red{\sf \blue{\longmapsto} Step-by-step\: Explanation:-}}}$

Given to points to us are :-

• ( 6 , -9)
• ( 1 , 3 )

Now , we can use Distance Formula , which is :-

$\boxed{\purple{\tt Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}}$

Here ,

• x1 = 6 .
• x2 = 1.
• y1 = (-9)
• y2 = 3.

→ Substituting the respective values ,

⇒ Distance = √ [ ( 6 - 1)² + ( 3 +9)² ] .

⇒ Distance = √ 5² + 12²

⇒ Distance = √ 25 + 144

⇒ Distance = √ 169 .

⇒ Distance = 13 units .

Hence the distance between two points is 13u.