Question

which equation shows the point-slope tor of the line that passes through (3, 2) and has a slope of 1/3
Y+ 2 = 1/3 (x + 3)
y -2 = 1/3 (x-3)
y+3 = 1/3 (x+3)
y - 3 = 1/3 (x - 2)

Answer 1

Answer:

y - 2 = $\frac{1}{3}$ (x - 3)

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Here m = $\frac{1}{3}$ and (a, b) = (3, 2) , thus

y - 2 = $\frac{1}{3}$(x - 3)

Answer 2

Given : A line passes through a point ( 3 , -2 ) and the slope of the line is ⅓ .

To Find : The equation of that line .

Solution : Here we are provided with a point ( 3 , -2 ) and slope of the line which is ⅓ . So clearly here to represent the line we will use point - slope form , which is ;

$\large\underline{\boxed{\red{\bf y - b = m ( x - a ) }}}$

Where ,

• a is x - coordinate.
• b is y - coordinate .
• m is the slope of the line .

Here ,

• a = 3
• b = -2
• m = ⅓ .

Now , put the respective values ;

$\boxed{\purple{\sf y - 2 = \dfrac{1}{3}(x-3)}}$