Answer:
1. 2.328×[tex]10^{22}[/tex]
2. 487
3. 30.52 OR 0 (see explanation↓)
Step-by-step explanation:
1.[tex](25)^{2t}[/tex]
(sub for t=8)
=[tex]25^{2*8}[/tex]
=[tex]25^{16}[/tex]
=2.328×[tex]10^{22}[/tex]
2.[tex]2st^{2} -5^{2}[/tex]
(sub for s=4 and t=8)
=2×4×[tex]8^{2}[/tex]-[tex]5^{2}[/tex]
=512-25
=487
3.[tex]2s^{2} -t^{3/16}[/tex] (the equation is not clear so I will do [tex]2s^{2} -\frac{t^{3} }{16}[/tex] as well)
FOR [tex]2s^{2} -t^{3/16}[/tex]
(sub s=4 and t=8)
=2×[tex]4^{2}[/tex]-[tex]8^{3/16}[/tex]
=32-1.476826146
=30.52 (to the nearest 2 decimal place)
FOR [tex]2s^{2} -\frac{t^{3} }{16}[/tex]
(sub s=4 and t=8)
=2×[tex]4^{2}[/tex]-[tex]\frac{8^{3} }{16}[/tex]
=32-32
=0
