CAN SOMEONE PLEASE HELP ME ASAP PLEASEE ANYBODY LITERALLY ANYONE OUT THERE PLEASE. Determine m∠ABQ and determine m∠BCR.
![CAN SOMEONE PLEASE HELP ME ASAP PLEASEE ANYBODY LITERALLY ANYONE OUT THERE PLEASE Determine mABQ and determine mBCR class=](https://us-static.z-dn.net/files/dd6/f11d33ba2275a6db9f941b9c7fed9123.png)
Answer:
ABQ = 139
BCR is the same as QBC since they are alternate interior angles
BCR = 41
Step-by-step explanation:
CBQ and SCB are same side interior angles so they add to 180
2a-9 + 5a +14 = 180
Combine like terms
7a +5 = 180
Subtract 5 from each side
7a = 175
Divide by 7
7a/7 = 175/7
a = 25
ABQ is the same as SCB since they are corresponding angles so
ABQ = SCB = 5a+14 = 5*25+14 = 125+14 = 139
BCR is the same as QBC since they are alternate interior angles
BCR = QBC = 2a-9 = 2*25 -9 = 50-9 = 41