Question

How much energy must be absorbed by water with a mass of 0.5 kg in order to raise the temperature from 30°c to 65°C?
Water has a specific heat of 4,190 j/kg°C

Answer 1

Answer:

Q = 67.04 [J]

Explanation:

In order to solve this problem, we must use the following equation of thermal energy, which relates mass to specific heat and temperature change.

$Q = m*c_{p}*(T_{2} -T_{1})$

where:

Q = thermal energy [J]

m = mass = 0.5 [kg]

Cp = specific heat = 4,190 [J/kg°C]

T2 = final temperature = 65 [C]

T1 = initial temperature = 30 [C]

Now replacing:

Q = 0.5*4.190*(65 - 30)

Q = 67.04 [J]