Respuesta :
radius of sphere = 18/2 = 9 cm
Volume of sphere = 4/3 πr^3 = 4/3 x π x (9)^3 = 972 π cubic cm
If the diameter is reduced by half, then
Volume = 4/3 x π x (9/2)^3 = 4/3 x π x (9)^3 x (1/2)^3 = 1/8(972)
Therefore, new volume is 1/8 of original volume.
Volume of sphere = 4/3 πr^3 = 4/3 x π x (9)^3 = 972 π cubic cm
If the diameter is reduced by half, then
Volume = 4/3 x π x (9/2)^3 = 4/3 x π x (9)^3 x (1/2)^3 = 1/8(972)
Therefore, new volume is 1/8 of original volume.
The volume of the sphere would be 1/8 of the original volume
How to determine the changes when the diameter is halved?
The volume of a sphere is:
V= π(d/2)³
When the diameter is halved, we have:
V2= π(d/2/2)³
This gives
V2= 1/8 * π(d/2)³
Substitute V= π(d/2)³
V2= 1/8V
Hence, the volume of the sphere would be 1/8 of the original volume
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