Question

In the diagram below of AACD, DB is a median to AC, and AB = DB.
D
A
B
c
If mZDAB = 32°, what is mZBDC?
(1) 320
(3) 58°
(2) 520
(4) 64°

Answer 1

Answer:

it will be (3)

Step-by-step explanation:

since DB is a median

then DB= half AC , AB=BC

then AB=BD

then the two triangles are isosceles

Answer 2

The required m∠BDC is 32° .

In geometry, a median of a triangle is a line segment joining a vertex to the midpoint of the opposite side, thus bisecting that side. Every triangle has exactly three medians, one from each vertex, and they all intersect each other at the triangle's centroid.

According to the given question ;

DB is a median;

By the symmetry ;

Then DB = half AC ,

        = AB = BC

Then= AB = BD

In a triangle, a line that connects one corner (or vertices ) to the middle point of the opposite side is called a median. A property of isosceles triangles, which is simple to prove using triangle congruence, is that in an isosceles triangle the median to the base is perpendicular to the base.

Then the two triangles are isosceles.

Means m∠DAB = m∠BDC = 32°

For the more information about the properties of isosceles triangle click the link given below.

https://brainly.in/question/13106654