Question

PLEASE HELP I ONLY HAVE 10 minutes !!! (will give brainliest )........Find the perimeter of AABC with vertices A(-5, -5), B(3, -5), and C(-5, 1).

(picture is included)

Answer 1

Answer:

24

Step-by-step explanation:

So to start we need to find the length of the sides. luckily, since this is a right triangle we can subtract the x values on line AB to get 8 and we can subtract the y values on line AC to get 6. Now that we know two lengths we can use $A^{2} +B^{2} =C^{2}$ to find the last length.

When we plug in the two known lengths we get $8^{2} +6^{2} =c^{2}$ which can be simplified to $64+36=c^{2}$ and then simplified again to be $100=c^{2}$. We can then take the square root of 100 to know that c=10.

Finally, we can add $10+8+6$ to get 24.