Question

If 50 grams of sodium reacts with chlorine to form 126 grams of salt. How many grams of chlorine reacted?

Answer 1

Answer:

$m_{Cl_2}=76g$

Explanation:

Hello.

In this case, since the undergoing chemical reaction is:

$2Na+Cl_2\rightarrow 2NaCl$

By means of the law of concentration of mass which states that matter cannot be created nor destroyed, during a chemical reaction, the mass of the resulting products equal the mass of the initial reactants, in this case:

$m_{Na}+m_{Cl_2}=m_{NaCl}$

Since the mass of sodium is 50 g and the mass of NaCl is 126 g, the mass of chlorine reacted is:

$m_{Cl_2}=m_{NaCl}-m_{Na}=126g-50g\\\\m_{Cl_2}=76g$

Best regards!

Answer 2

The mass of chlorine that reacted is 76 g.

The chemical equation can be represented as follows:

Na + Cl → NaCl

Using the law of conservation of mass which states that mass can neither

be created nor destroy but can be transformed from one form to another.

This simply means the amount of reactant should be equal to the amount

of product.

Therefore,

Na = 50g

Cl = ?

NaCl = 126 g

Mass of Cl that reacted = 126 - 50  = 76 g

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