1. Layne rode his bike from Point A to B by
using Cherry Street. How much further would
his trip have been if he took Orange Drive
and Peach Avenue instead?

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1 Layne rode his bike from Point A to B by using Cherry Street How much further would his trip have been if he took Orange Drive and Peach Avenue instead PLEASE class=

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Answer:

cherry street is 85 yards, while orange dr. and peach ave. is 113 yards, meaning that cherry st. is 28 yards faster

Step-by-step explanation:

(85 x 85) - (77 - 77) = 1296

square root of 1296 is 36

77 + 36 = 113

113 - 85 = 28

this means that cherry st. is 28 yds faster

using the Pythagorean Theorum

The distance that Layne would have to travel further if he took the given paths is required.

If Layne took Orange Drive and Peach Avenue instead his trip would be 28 yards longer.

Pythagoras theorem

c = Length of Cherry st. = 85 yards

a = Length of Orange dr.

b = Length of Peach av. = 77 yards

The angle between orange drive and peach avenue has been assumed to be [tex]90^{\circ}[/tex].

We need to find the sum of the distances of the paths orange drive and peach avenue.

So, we need to find the length of orange drive.

Applying the Pythagoras theorem

[tex]a^2+b^2=c^2\\\Rightarrow a=\sqrt{c^2-b^2}\\\Rightarrow a=\sqrt{85^2-77^2}\\\Rightarrow a=36\ \text{yards}[/tex]

The distance traveled when orange drive and peach avenue is taken is

[tex]36+77=113\ \text{yards}[/tex]

The extra distance traveled

[tex]113-85=28\ \text{yards}[/tex]

Learn more about Pythagoras theorem:

https://brainly.com/question/343682

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