Respuesta :
Answer:
yall need to stop lying Imao Negative StartFraction 49 over 4 EndFraction divided by StartFraction 7 over 2 EndFraction
Step-by-step explanation:
The expression that finds the change in temperature per hour for this considered case is given by: Option D: [tex]\dfrac{-47/4}{7/2}[/tex]
How to measure the rate of change of something as some other value changes?
Suppose that we have to measure the rate of change of y as x changes, then we have:
[tex]Rate = \dfrac{y_2 - y_1}{x_2 - x_1}[/tex]
where we have
[tex]\rm when \: x=x_1, y = y_1\\when\: x = x_2, y= y_2[/tex]
Remember that, we divide by the change in independent variable so that we get some idea of how much the dependent quantity changes as we change the independent quantity by 1 unit.
(5 change per 3 unit can be rewritten as 5/3 change per 1 unit)
For this case, we're specified that:
- Initial temperature = 0 degrees.
- Final temperature = [tex]-12 \dfrac{1}{4}[/tex] degrees.
- Time taken for this change = [tex]3\dfrac{1}{2}[/tex] hours
Expressing final temperature in simple form:
[tex]-12\dfrac{1}{4} = -12 + \dfrac{1}{4} = \dfrac{-12 \times 4}{4} + \dfrac{1}{4} = \dfrac{-47}{4}[/tex]
Expressing time taken for the considered temperature change in simple forms:
[tex]3\dfrac{1}{2} = 3 + \dfrac{1}{2} = \dfrac{3 \times 2}{2} + \dfrac{1}{2} = \dfrac{7}{2}[/tex]
The temperature depends on time.
Suppose that:
x = time, y = temperature
Then, suppose that:
- [tex]x_1[/tex] = Time when temperature was [tex]y_1 = 0[/tex] degrees.
- [tex]x_2[/tex] = Time when temperature was [tex]y_2 = -\dfrac{47}{4}[/tex] degrees.
Then, the rate of change of temperature would be:
[tex]Rate = \dfrac{y_2 - y_1}{x_2 - x_1}[/tex]
The change in time is: [tex]x_2 - x_1 =\dfrac{7}{2}[/tex] (in hours).
Thus, we get:
[tex]Rate = \dfrac{y_2 - y_1}{x_2 - x_1} = \dfrac{-47/4 - 0}{7/2} = \dfrac{-47/4}{7/2}[/tex]
Thus, the expression that finds the change in temperature per hour for this considered case is given by: Option D: [tex]\dfrac{-47/4}{7/2}[/tex]
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