Question

A box of mass 44 kg is pushed hard enough to set it in motion across a flat surface. The coefficient of kinetic friction between the box and the surface µk = 0.48. What minimum pushing force is needed to keep the box moving at a constant velocity?
a 231n
b 207n
c 178n
d 283n

Answer 1

Answer:

207

Explanation:

For the box to move at a constant velocity, the applied force must cancel the force due to kinetic friction.

F = mu_k * N

N = normal force = weight (= mg) if sliding horizontally

F = mu_k * mg = (0.48)(44 kg)(9.8 m/s^2) = 207 N