Answer these two questions in steps plz

Answer:
To solve the above equation we will follow the BODMAS rule.
It stands for :
[tex]\quad\begin{gathered} \small \begin{array}{l} \star \: \rm B= bracket \\\star \: \rm O= order \: of \: power \: \\\star \: \rm D= division \\\star \: \rm M= multiplication \\ \star \: \rm A= addition \\ \star \: \rm S=subtraction \end{array}\end{gathered}[/tex]
Solving the questions by bodmas rule :
[tex]1) \: \pmb{\sf{(6 + \sqrt{26 - 1} ) \div ( {3}^{2} + 2) }}[/tex]
[tex] = {\sf{(6 + \sqrt{26 - 1} ) \div ( {3}^{2} + 2) }}[/tex]
[tex] = {\sf{(6 + \sqrt{25} ) \div ( {(3 \times 3)} + 2) }}[/tex]
[tex] = {\sf{(6 + \sqrt{5 \times 5} ) \div ( 9 + 2) }}[/tex]
[tex] = {\sf{(6 + 5 ) \div (9 + 2) }}[/tex]
[tex] = {\sf{(11 ) \div (11) }}[/tex]
[tex] = {\sf{11 \div 11}}[/tex]
[tex] ={\underline{\boxed{\tt{\red{1}}}}}[/tex]
Hence, the answer is 1.
[tex]\begin{gathered}\end{gathered}[/tex]
[tex]2) \: \pmb{\sf{17 - 5 \times 2 \div \sqrt{100}}}[/tex]
[tex]{\sf{ = 17 - 5 \times 2 \div \sqrt{100}}}[/tex]
[tex]{\sf{ = 17 - 5 \times 2 \div \sqrt{2 \times 2 \times 5}}}[/tex]
[tex]{\sf{ = 17 - 5 \times 2 \div \sqrt{ \underline{2 \times 2}\times \underline{5}}}}[/tex]
[tex]{\sf{ = 17 - 5 \times 2 \div (2 \times 5)}}[/tex]
[tex]{\sf{ = 17 - 5 \times 2 \div 10}}[/tex]
[tex]{\sf{ = 17 - 5 \times 0.2}}[/tex]
[tex]{\sf{ = 17 - 1}}[/tex]
[tex] ={\underline{\boxed{\tt{\red{16}}}}}[/tex]
Hence, the answer is 16.
[tex]\underline{\rule{220pt}{3pt}}[/tex]