Respuesta :

Not sure on the second one, but I did them both on my calculator, so it should be right. :)
Ver imagen ClutchJDawg23

Answer:

Solution :

To solve the above equation we will follow the BODMAS rule.

  • >> BODMAS is an order of mathematic operations.
  • >> BODMAS rule is to be followed while solving expressions in mathematics.

It stands for :

[tex]\quad\begin{gathered} \small \begin{array}{l} \star \: \rm B= bracket \\\star \: \rm O= order \: of \: power \: \\\star \: \rm D= division \\\star \: \rm M= multiplication \\ \star \: \rm A= addition \\ \star \: \rm S=subtraction \end{array}\end{gathered}[/tex]

Solving the questions by bodmas rule :

[tex]1) \: \pmb{\sf{(6 + \sqrt{26 - 1} ) \div ( {3}^{2} + 2) }}[/tex]

[tex] = {\sf{(6 + \sqrt{26 - 1} ) \div ( {3}^{2} + 2) }}[/tex]

[tex] = {\sf{(6 + \sqrt{25} ) \div ( {(3 \times 3)} + 2) }}[/tex]

[tex] = {\sf{(6 + \sqrt{5 \times 5} ) \div ( 9 + 2) }}[/tex]

[tex] = {\sf{(6 + 5 ) \div (9 + 2) }}[/tex]

[tex] = {\sf{(11 ) \div (11) }}[/tex]

[tex] = {\sf{11 \div 11}}[/tex]

[tex] ={\underline{\boxed{\tt{\red{1}}}}}[/tex]

Hence, the answer is 1.

[tex]\begin{gathered}\end{gathered}[/tex]

[tex]2) \: \pmb{\sf{17 - 5 \times 2 \div \sqrt{100}}}[/tex]

[tex]{\sf{ = 17 - 5 \times 2 \div \sqrt{100}}}[/tex]

[tex]{\sf{ = 17 - 5 \times 2 \div \sqrt{2 \times 2 \times 5}}}[/tex]

[tex]{\sf{ = 17 - 5 \times 2 \div \sqrt{ \underline{2 \times 2}\times \underline{5}}}}[/tex]

[tex]{\sf{ = 17 - 5 \times 2 \div (2 \times 5)}}[/tex]

[tex]{\sf{ = 17 - 5 \times 2 \div 10}}[/tex]

[tex]{\sf{ = 17 - 5 \times 0.2}}[/tex]

[tex]{\sf{ = 17 - 1}}[/tex]

[tex] ={\underline{\boxed{\tt{\red{16}}}}}[/tex]

Hence, the answer is 16.

[tex]\underline{\rule{220pt}{3pt}}[/tex]

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