Question

The equilibrium constant for A + 2B → 3C is 2.1 * 10^-6
Determine the equilibrium constant for 2A + 4B → 6C.
a- 4.2 * 10^-6
b- 4.4 * 10^-12
c- 2.3 *10^11
d- 1.8 *10^-11
e- None of these

Answer 1

Answer:

b- 4.4 * 10^-12.

Explanation:

Hello.

In this case, as the reaction:

A + 2B → 3C

Has an equilibrium expression of:

$K_1=\frac{[C]^3}{[A][B]^2}=2.1x10^{-6}$

If we analyze the reaction:

2A + 4B → 6C

Which is twice the initial one, the equilibrium expression is:

$K_2=\frac{[C]^6}{[A]^2[B]^4}$

It means that the equilibrium constant of the second reaction is equal to the equilibrium constant of the first reaction powered to second power:

$K_2=K_1^2$

Thus, the equilibrium constant of the second reaction turns out:

$K_2=(2.1 * 10^{-6})^2\\\\K_2=4.4x10^{-12}$

Therefore, the answer is b- 4.4 * 10^-12.

Best regards.