[tex]\large\underline{\bf \red{Step \:by\: Step \:Explanation:}}[/tex]
Let us take ,
Also let us consider x > y .
According to first Condition :-
⇒ x - y = 1.
⇒ x = y + 1. .............(i)
According to second Condition :-
⇒ x × y = 30 .
⇒ ( y + 1 )y = 30 . [ From (i) ]
⇒ y² + y = 30.
⇒ y² + y - 30 = 0 .
⇒ y² + 6y - 5y -30 = 0.
⇒ y ( y + 6 ) -5 ( y + 6 ) = 0 .
⇒ ( y + 6 ) ( y - 5 ) = 0 .
[tex]\red{\bf \longmapsto y = 5 , (-6)}[/tex]
Here y can sustain both values 5 and minus 6 as y is an integer.
So , x = -6 , 5 .
Hence possible answers are ,
[tex]\boxed{\purple{\bf x = -6 , y = -5 }}[/tex]
[tex]\qquad\qquad\qquad \bf Or [/tex]
[tex]\boxed{\purple{\bf x = 6 , y = 5 }}[/tex]
.
