Answer:
Options (A) and (C)
Step-by-step explanation:
Let the equation represented by the table is,
y - y' = m(x - x')
where m = slope of the line
(x', y') are the coordinates of a point passing through the line.
Since, slope of the line 'm' = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
Let the two points given in the table are (0, 11) and (1, 5)
Therefore, slope 'm' = [tex]\frac{11-5}{0-1}[/tex] = -6
Now equation of the line passing through (0, 11) will be,
y - 11 = -6(x - 0)
Equation of the line passing through (1, 5) and slope (-6) will be,
y - 5 = -6(x - 1)
Equation of the line passing through (2, -1) and slope (-6) will be,
y + 1 = -6(x - 2)
Equation of the line passing through (3, -7) and slope (-6) will be,
y + 7 = -6(x - 3)
Therefore, equations given in Options (A) and (C) will be the answer.
