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  • 26-09-2016
  • Chemistry
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how many grams of nitrogen must be used to form 106 grams of ammonia

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  • 26-09-2016
N₂      +          3H₂ ⇒ 2NH₃
1mol                :          2mol
28g                  :          34g
x                       :          106g

[tex]x=\frac{106g*28g}{34g}\approx87,29g[/tex]
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