Question

15 points!!!
4x^2 -20x +25≥0​

Answer 1

Answer:

x ≥ $\frac{5}{2}$

Step-by-step explanation:

Given equation:

     4x² -20x + 25≥0​

To solve for x, we simply factorize the equation;

We should find two numbers whose sum = -20 and product is 100

  These two numbers are -10 and -10

So;

    4x² - 10x - 10x + 25 ≥ 0​

   factorize;

    2x(2x - 5) - 5(2x - 5) ≥ 0​

   (2x - 5) (2x - 5) ≥ 0​

    So;

        2x - 5 ≥ 0​

         2x ≥ 5

            x ≥ $\frac{5}{2}$