What are the roots of the quadratic equation y=x^2 - 10x +125?
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Answer:Look at the step by step it’s correct
Step-by-step explanation:
A quadratic equation is an equation whose leading coefficient is of second degree also the equation has only one unknown while it has 3 unknown numbers. The correct option is D.
A quadratic equation is an equation whose leading coefficient is of second degree also the equation has only one unknown while it has 3 unknown numbers. It is written in the form of ax²+bx+c.
Suppose that the given quadratic equation is
ax² + bx + c = 0
Then its roots are given as:
[tex]x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}[/tex]
For the given equation, the value of a, b, and c is 1, -10, and 125, respectively. The roots of the given quadratic equation are,
[tex]x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}\\\\x = \dfrac{-(-10) \pm \sqrt{(-10)^2 - 4(1)(125)}}{2(1)}\\\\x = \dfrac{10 \pm \sqrt{100 - 500}}{2}\\\\x = \dfrac{10 \pm 20i}{2}\\\\[/tex]
x = 5 ± 10i
Hence, the correct option is D.
Learn more about Quadratic Equations:
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