WILL GIVE BRAINLIEST

12) The chemical formula for phosphorus trichloride is PCl3. In one to two sentences, explain how you would build a ball-and-stick model of phosphorus trichloride. Include a description of the parts of the model.(2 points)

13) Copper (Cu) reacts with sulfur (S) to form copper sulfide as shown in the chemical equation. A scientist adds 4 grams of Cu to 2 grams of S to start the reaction. At the end of the experiment, she has 6 grams of product. In one to two sentences, explain what would happen if the scientist increased the amount of copper to 6 grams, and why. (1 point)

12) In the ball and stick model, an orange ball representing the phosphorus atom and three green balls representing chlorine atoms are connected by means of sticks that are coloured halfway green and orange respectively to represent the shared electrons between phosphorus and chlorine with the chlorine atoms forming the base of a triangular pyramid while the phosphorus atom forms the top of the pyramid.

13) The scientist will have 6 grams of product as before but will have two grams of unreacted copper atoms because the mass ratio of copper to sulfur in this reaction is 2:1

Explanation:

12) Phosphorus trichloride has a trigonal pyramidal structure and is composed of three atoms of chlorine and one atom of phosphorus.

In the ball and stick model, an orange ball representing the phosphorus atom and three green balls representing chlorine atoms are connected by means of sticks that are coloured halfway green and orange respectively to represent the shared electrons between phosphorus and chlorine with the chlorine atoms forming the base of a triangular pyramid while the phosphorus atom forms the top of the pyramid.

13) The reaction between copper and sulfur to form copper sulfide is shown in the equation below:

Cu + S ---> CuS

1 mole of copper reacts with 1 mole of sulfur to produce 1 mole of copper sulfide

molar mass of copper = 64 g/mol; molar mass of sulfur = 32 g/mol, molar mass of copper sulfide = 96 g/mol

mass ratio of copper to sulfur = 63 g/ 34 g = 2

This means that 2 grams of copper will react with 1 g of sulfur to produce 3 grams of product. similarly, 4 g of copper will react with 2 g of sulfur to produce 6 grams of product.

Therefore 6 g of of copper will react with 3 g of sulfur. However, since the amount of sulfur available for reaction is 2 g only, 2 g of copper will be left unreacted after 4 g has reacted completely with 2 g of sulfur to produce 6 g of copper sulfide.