Let us see how we can solve this step by step each :
6417 ÷ 31 , we divide 64 by 31 and get the resulting quotient as 2 .
Then we bring down 1 . So , the number below is 21 , which cannot be divided by 31 .
So , we will have to bring down 7 for which we have to add a 0 to the quotient . Then the quotient will become 20 as of now .
As 217 is divisible by 3 , I put seven near 21 , making the quotient as 217 and get the remainder 0 .
Hence in the correct solution the correct quotient = 207 .
In Xavier's solution :
But the same thing has not been done in Xavier's solution as he has put a 0 after 7 instead of putting it before 7 . Hence , Xavier's mistake is that he put the 0 after 7 instead of putting it before 7 .
In Xavier's solution the quotient is = 270
Therefore , Xavier's mistake is that he put the 0 after 7 instead of putting it before 7 .
