Answer:
0.0806
Step-by-step explanation:
From the given information:
Number of toss = 50
The probability of having a head = 1/2 = 0.5
The Probability of 8th head occur on 12th toss can be computed as :
Pr(8th head occur on 12th toss) = Pr(7 heads in 11 toss) × P(8th head on 12th toss)
Pr(8th head occur on 12th toss) = C(11,7) × 0.5⁷ × (1 - 0.5)⁴ * 0.5
Pr(8th head occur on 12th toss) = [tex]\dfrac{11!}{7!(11-7)!}[/tex] × 0.5⁷ × (1 - 0.5)⁴ × 0.5
Pr(8th head occur on 12th toss) = 0.0806
Answer:
The probability of 8th heads,
That is occurred on 12th toss.
Step-by-step explanation:
A coin is tossed 50 times.
There are two possible outcomes of occurring a head or tail.
Probability of occurring head = no.of head/ possible outcomes
= 1/2
Total number of tossing a coin= 50 times
Probability of 8th heads occurs on 12th toss:
12C8 (1/2)8 (1/2)9 (1/2)10 (1/2)11 (1/2)12
= 12C8 (1/2)8+9+10+11+12
= 12C8 (1/2)50
= 12C8 / 250
= 495 / 1125899906842624
= 4396.48317752 x 10-16
This is the probability of 8th heads,
That is occurred on 12th toss.
