Answer:
The answer is "The last memory addresses used by a specific program is 2CF0".
Explanation:
For this specific problem, we assume that only a memory storage allocation like Array data structure is needed, as well as any allocation only needs one memory cell since it focuses on the structure and type of data used.
So, first, we will transform the provided memory address for better comprehension from Hexadecimal into decimal.
[tex]\to \bold{(2C8D)_{16} = (11405)_{10}}[/tex]
Now 11405 is the first memory cell's address. With all of this number, it can add 99, resulting in the final decimal memory address.
[tex]=11405 + 99\\\\= 11504[/tex]
[tex]\bold{(11504)_{10} = (2CF0)_{16}}.[/tex]