Answer:
630
Step-by-step explanation:
Given that:
First flip = 72 coins
For each coin which is a head, you roll = 5, six-sided dice
Thus, the expected sum on a single six-sided dice = [tex]\sum x P(x)[/tex]
[tex]\sum x P(x)[/tex] = [tex]\dfrac{1}{6}\times (1+2+3+4+5+6)[/tex]
[tex]\sum x P(x)[/tex] = 3.5
Thus, the expected sum on the five six-sided dice = 5 × 3.5 = 17.5
However, for a single flip :
The expected sum = P(heads) × expected sum on 5 dice + P(tails) × expected sum on 0 dice.
Expected sum = [tex]\dfrac{1}{2} \times 17.5 + \dfrac{1}{2} \times 0[/tex]
Expected sum = 8.75
Hence, the expected total score from this game = 72 × 8.75 = 630