Respuesta :

Answer:

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Step-by-step explanation:

please find the correct question:

Given value:  

[tex]\to 4x \equiv 2(mod\ n) \ \ \ \ \ \ \ \ \ \ \ \ _{where} \ \ n=6\\\\\to 4x \equiv 2 (mod 6)[/tex]

[tex]\to 4x-2[/tex] should be divisible by 6  we are also given that [tex]0 \leq x < n[/tex]  and start with x = 0  

[tex]\to 4x-2[/tex] =-2 which is not divisible by 6  

x= 1  

[tex]\to 4x-2[/tex] = 2 not divisilble by 6  

x= 2

[tex]\to 4x-2[/tex] = 6 which is divisible by 6  

x=3  

[tex]\to 4x-2[/tex] = 10 not divisible by 6

x=4  

[tex]\to 4x-2[/tex]  = 14 not divisible by 6  

x=5

[tex]\to 4x-2[/tex]  = 18 which is divisible by 6  

so such x are x = 2 and x = 5

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