Answer:
please find the solution:
Step-by-step explanation:
please find the correct question:
Given value:
[tex]\to 4x \equiv 2(mod\ n) \ \ \ \ \ \ \ \ \ \ \ \ _{where} \ \ n=6\\\\\to 4x \equiv 2 (mod 6)[/tex]
[tex]\to 4x-2[/tex] should be divisible by 6 we are also given that [tex]0 \leq x < n[/tex] and start with x = 0
[tex]\to 4x-2[/tex] =-2 which is not divisible by 6
x= 1
[tex]\to 4x-2[/tex] = 2 not divisilble by 6
x= 2
[tex]\to 4x-2[/tex] = 6 which is divisible by 6
x=3
[tex]\to 4x-2[/tex] = 10 not divisible by 6
x=4
[tex]\to 4x-2[/tex] = 14 not divisible by 6
x=5
[tex]\to 4x-2[/tex] = 18 which is divisible by 6
so such x are x = 2 and x = 5