Answer: see below
Step-by-step explanation:
[tex]32)\quad \dfrac{3}{5}(x-12)>x-24[/tex]
3(x - 12) > 5(x - 24)
3x - 36 > 5x - 120
-5x -5x
-2x - 36 > -120
+36 +36
-2x > -84
÷ -2 ↓ ÷ -2
x < 42
Graph: ←------------o
42
34) 6[5y - (3y - 1)] ≥ 4(3y - 7)
6[5y - 3y + 1] ≥ 4(3y - 7)
6{2y + 1] ≥ 4(3y - 7)
12y + 6 ≥ 12y - 28
-12y -12y
6 ≥ -28
TRUE so the solution is All Real Numbers
Graph: ←-----------------------→
36) BC + AC > AB
4 + 8 - AB > AB
12 - AB > AB
+AB +AB
12 > 2AB
÷2 ÷2
6 > AB
AB < 6
[tex]38)\quad \dfrac{1}{2}(y-16)\geq y+2\quad ;\text{claim}\ y\leq 20[/tex]
Check: let y = 16
then [tex]\frac{1}{2}[/tex](16 - 16) ≥ 16 + 2
0 ≥ 18
FALSE so the claim is wrong
40) question not provided in the image so I cannot give a solution.
