Answer:
6.34 m/s
Explanation:
Given that,
A basketball player leave the ground to rise 2.05 m above the floor in an attempt to get the ball.
We need to find the velocity must a basketball player leave the ground. Using equation of kinematics as follows :
[tex]v^2-u^2=2ah[/tex]
As it leaves the ground, its final velocity, v = 0
a = -g (opposite to gravity)
[tex]-u^2=-2gs\\\\u^2=2\times 9.8\times 2.05\\\\u=6.338\ m/s[/tex]
or
u = +6.34 m/s