I'm confused on how to find x
![Im confused on how to find x class=](https://us-static.z-dn.net/files/d81/1a883203215a51f379ac24378f830ebe.jpg)
Answer:
x = 2
Step-by-step explanation:
Since this is a 45-45-90 triangle, the 2 legs will be the same, meaning that y will also be [tex]\sqrt2[/tex].
We can then solve for x using the Pythagorean theorem:
[tex]\sqrt2^2+\sqrt2^2=x^2\\2+2=x^2\\4=x^2\\x=2[/tex]
Or, we could use a quicker approach: if the triangle is a 45-45-90 triangle, the hypotenuse will be [tex]\sqrt2[/tex] times the length of 1 leg. It essentially does the same thing; it's just faster so you could save time on tests.