Question

(Surds)

Write

√99 + √44

in the form a√b where a and b are integers

Answer 1

Because we know that $9 (11) = 99$ and $4(11) = 44$ then we can deduce that the simplified integer form must be $\sqrt{9} (\sqrt{11} )$ & $\sqrt{4} (\sqrt{11})$. So the correct answer becomes $3\sqrt{11} +2\sqrt{11}$, this means the final answer is $5\sqrt{11}$.

Answer 2

The value of a and b is 7 and 10. Then the expression √99 + √44 can be written as in the form a√b is 7√10

What is an irrational number?

If the value of a numerical expression is terminating then they are the rational number then they are called the rational number and if the value of a numerical expression is non-terminating then they are called an irrational number.

Write √99 + √44 in the form a√b where a and b are integers, then we have

The expression can be written as

3√10 + 4√10

(3 + 4)√10

7√10

More about the irrational number link is given below.

https://brainly.com/question/9466779