A 7.212 g sample of hydrated salt is heated until a constant mass is obtained. The mass of the anhydrous salt is 3.524. What is the percent by mass of water in the original hydrated salt sample in % H20?
![A 7212 g sample of hydrated salt is heated until a constant mass is obtained The mass of the anhydrous salt is 3524 What is the percent by mass of water in the class=](https://us-static.z-dn.net/files/da0/da9a2056a737304dff411842f3a6dd2f.jpg)
Answer:
51.14%
Explanation:
The following data were obtained from the question:
Mass of hydrated salt = 7.212 g
Mass of anhydrous salt = 3.524 g
Percentage mass of water =..?
Next, we shall determine the mass of the water in the hydrated salt. This can be obtained as follow:
Mass of hydrated salt = 7.212 g
Mass of anhydrous salt = 3.524 g
Mass of water =.?
Mass of water = (Mass of hydrated salt) – (Mass of anhydrous salt)
Mass of water = 7.212 – 3.524
Mass of water = 3.688 g
Finally, we shall determine the percentage mass of water in the hydrated salt as follow:
Percentage of water
= mass of water /mass of hydrated salt × 100
Percentage of water = 3.688/7.212 × 100
Percentage of water = 368.8/7.212
Percentage of water = 51.14%
Therefore, the percentage of water in the hydrated salt is 51.14%