Question

7. Find two consecutive even integers such that twice the smaller is
26 less than 3 times the larger.

Answer 1

Answer:

           20 and 22

Step-by-step explanation:

The difference between two consecutive even integers  is 2

and even integer is always twice some integer

So:

2x   ← smaller of numbers

2x+2  ←  larger of numbers  

2×2x     ←  twice the smaller of numbers

3(2x+2)      ←  three  times the larger

3(2x+2)-26   ← 26 less than 3 times the larger

twice the smaller is  26 less than 3 times the larger:

3(2x+2) - 26 = 2×2x

6x + 6 - 26 = 4x

       +20         +20

6x - 4x = 20

       2x = 20

2x+2 = 20 + 2 = 22        

Check:   2×20=40; 40+26 = 66; 66÷3=22