Question

Which shows one way to determine the factors of x3 + 5x2 – 6x – 30 by grouping?

x(x2 – 5) + 6(x2 – 5)
x(x2 + 5) – 6(x2 + 5)
x2(x – 5) + 6(x – 5)
x2(x + 5) – 6(x + 5)

Answer 1

Answer:

D

Step-by-step explanation:

group them first :

( x3+5x2) and ( -6x-30)

then simply by gcf ( greatest common factor) :

x2(x+5) and -6(x+5)

and just add them together:

x2(x+5)-6(x+5)

bonus :

it can be written as (x2-6)(x+5)

Answer 2

The answer choice which shows how to determine the factors of the expression by grouping is; Choice D; x²(x + 5) – 6(x + 5)

Factorisation by grouping

The given expression is; x³ + 5x² – 6x – 30.

The expression is tetranomial, hence, by grouping into 2 terms each; we have;

• (x³+ 5x²) (– 6x – 30)

Ultimately, upon factorisation of each subunit of the expression, we have;

• x²(x+5) -6(x+5)

Read more on factorisation by grouping;

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