Respuesta :
Answer:
1061.32 miles apart
Step-by-step explanation:
Given that both planes A and B leave the same place and travel in perpendicular directions one in north and other in east.
The planes position at any time along with starting point can be visualized as a right triangle with sides equal to distances travelled by both the planes, and hypotenuse the distance between the planes, and the place Tulsa the vertex right angled.
Plan A starts at 2.00 with speed 300 mph
Hence at 5 p.m. distance travelled by plane A = 300(3) = 900 miles
Plane B starts at 2.30 with speed 225 mph
At 5 p.m. distance travelled = 225(2.50) = 562.50
Hence distance between the planes = length of hypotenuse
=[tex]\sqrt{900^2+562.5^2} \\=\sqrt{810000+316406.25} \\=1061.32 miles[/tex]
The two planes are 1061.32 miles apart
