Question

what is the last term of (2x-4)2

Answer 1

Answer:   16

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Explanation:

The full expanded expression is 4x^2-16x+16

Which you can get through these steps

(2x-4)^2

(2x-4)(2x-4)

y(2x-4) ...... let y = 2x-4

2xy - 4y

2x( y ) - 4( y )

2x( 2x-4) - 4( 2x-4 ) .... plug in y = 2x-4

4x^2 - 8x - 8x + 16

4x^2 - 16x + 16

Answer 2

The question is an illustration of expansion and factorization.

The last term of the expression is 16.

We have:

$(2x - 4)^2$

Expand

$(2x - 4)^2 = (2x - 4) \times (2x - 4)$

Further expand

$(2x - 4)^2 = 2x(2x - 4) - 4(2x - 4)$

Open brackets

$(2x - 4)^2 = 4x^2 - 8x - 48x + 16$

$(2x - 4)^2 = 4x^2 - 56x + 16$

Hence, the last term of the expression is 16.

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