Suppose that y varies jointly with w and x and inversely with z and y = 400 when w = 10, x = 25, and z = 5. Write the equation that models the relationship.

Respuesta :

Answer:

[tex]y =8 \cdot \frac{wx}{z}[/tex]

Step-by-step explanation:

Joint variation says that:

If y varies jointly with x and inversely with z

i.e,

[tex]y \propto x[/tex]

[tex]y \propto \frac{1}{z}[/tex]

then the equation is in the form of :

[tex]y = k\frac{x}{z}[/tex] where, k is the constant of variation.

As per the statement:

Suppose that y varies jointly with w and x and inversely with z

by definition of joint variation we have;

[tex]y = k\frac{wx}{z}[/tex]            ......[1]

It is given that: y = 400 when w = 10 , x = 25 and z = 5

Substitute in [1] we have;

[tex]400 = k \cdot \frac{10 \cdot 25}{5}[/tex]

Simplify:

[tex]400 = 50k[/tex]

Divide both sides by 50 we have;

8 = k

or

k = 8

⇒[tex]y =8 \cdot \frac{wx}{z}[/tex]

Therefore, the equation that models the relationship is, [tex]y =8 \cdot \frac{wx}{z}[/tex]

The equation that models the relationship between w, x, y, and z is shown below.

[tex]\rm y = 8 \times \dfrac{xw}{z}[/tex]

What are ratio and proportion?

A ratio is an ordered couple of numbers a and b, written as a/b where b can not equal 0. A proportion is an equation in which two ratios are set equal to each other.

y varies jointly with w and x and inversely with z

[tex]\rm y \propto wx \\\\y \propto \dfrac{1}{z}[/tex]

Then we have

[tex]\rm y = k \ \dfrac{xw}{z}[/tex]

y = 400 when w = 10, x = 25, and z = 5. Then we have

[tex]\rm 400 = k \times \dfrac{10*25}{5}\\\\\\k \ \ \ = \dfrac{400*5}{10*25}\\\\\\k \ \ \ = 8[/tex]

Then we have

[tex]\rm y = 8 \times \dfrac{xw}{z}[/tex]

More about the ratio and the proportion link is given below.

https://brainly.com/question/14335762

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