Question

What are the solutions of this quadratic equation? 4x^2 - 40x + 109=0
A. X= -5 +- 3/2i
B. X= 5+- 3/2i
C. X= -5 +- 12i
D. X= 5+- 12i

Answer 1

Answer:

D. X= 5+- 12i

Hope this correct

Answer 2

The solution of the quadratic equation 4$x^{2}$ - 40$x$ + 109 = 0  is  $x={5 \pm \frac{3i}{2}$ which is option b.

What is quadratic equation?

Quadratic Equation Definition. The polynomial equation whose highest degree is two is called a quadratic equation or sometimes just quadratics.

Quadratic equations A quadratic equation contains terms up to $x^{2}$. There are many ways to solve quadratics. All quadratic equations can be written in the form (a$x^{2}$ + b$x$ + c = 0) where (a), (b) and (c) are numbers ( (a) cannot be equal to 0, but (b) and (c) can be).

$x=\frac{-b \pm ( \sqrt{b^2-4ac} }{2a}$

Given,

4$x^{2}$ - 40$x$ + 109 = 0

Here

a = 4, b = -40 and c = 109

Put values in above formula

$x=\frac{40 \pm ( \sqrt{(-40)^2-1744} }{8}$

$x=\frac{40 \pm ( \sqrt{-144} }{8}$

$x=\frac{40 \pm 12( \sqrt{-1} }{8}$

$x={5 \pm \frac{3i}{2}$

Hence, The solution of the quadratic equation 4$x^{2}$ - 40$x$ + 109 = 0  is $x={5 \pm \frac{3i}{2}$ .

Learn more about Equations:

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