Respuesta :

Answer:

[tex](2,6)[/tex]

Step-by-step explanation:

Solve by substitution. Solve the second equation for x:

[tex]x+6y=38\\\\x+6y-6y=38-6y\\\\x=38-6y[/tex]

Insert the value of x into the first equation:

[tex]5(38-6y)+y=16[/tex]

Solve for y. Simplify multiplication using the distributive property:

[tex]5(38)+5(-6y)+y=16\\\\190-30y+y=16\\\\190-29y=16[/tex]

Subtract 190 from both sides:

[tex]190-190-29y=16-190\\\\-29y=-174[/tex]

Isolate the variable to find its value. Divide both sides by -29:

[tex]\frac{-29y}{-29}=\frac{-174}{-29} \\\\y=6[/tex]

Now take the value of y and insert back into either equation to solve for x:

[tex]5x+6=16[/tex]

Subtract 6 from both sides:

[tex]5x+6-6=16-6\\\\5x=10[/tex]

Divide both sides by 5:

[tex]\frac{5x}{5}=\frac{10}{5}\\\\ x=2[/tex]

Therefore, the solution to the system is [tex](2,6)[/tex].

:Done

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