Answer:
[tex](2,6)[/tex]
Step-by-step explanation:
Solve by substitution. Solve the second equation for x:
[tex]x+6y=38\\\\x+6y-6y=38-6y\\\\x=38-6y[/tex]
Insert the value of x into the first equation:
[tex]5(38-6y)+y=16[/tex]
Solve for y. Simplify multiplication using the distributive property:
[tex]5(38)+5(-6y)+y=16\\\\190-30y+y=16\\\\190-29y=16[/tex]
Subtract 190 from both sides:
[tex]190-190-29y=16-190\\\\-29y=-174[/tex]
Isolate the variable to find its value. Divide both sides by -29:
[tex]\frac{-29y}{-29}=\frac{-174}{-29} \\\\y=6[/tex]
Now take the value of y and insert back into either equation to solve for x:
[tex]5x+6=16[/tex]
Subtract 6 from both sides:
[tex]5x+6-6=16-6\\\\5x=10[/tex]
Divide both sides by 5:
[tex]\frac{5x}{5}=\frac{10}{5}\\\\ x=2[/tex]
Therefore, the solution to the system is [tex](2,6)[/tex].
:Done