The required magnitude of the average force exerted on the car is 1269 N.
Given data:
The mass of truck is, m = 2350 kg.
The distance covered is, s = 25 m.
The initial speed of truck is, u = 3 m/s.
The final speed of truck is, v = 6 m/s.
As per the Newton's second law, the applied force is the product of mass and acceleration. Then,
F = ma
And by third kinematic equation of motion as,
[tex]v^{2}= u^{2}+2as\\\\a=\dfrac{v^{2}-u^{2}}{2s}[/tex]
Solving as,
[tex]F=m \times \dfrac{v^{2}-u^{2}}{2s}\\\\F=2350 \times \dfrac{6^{2}-3^{2}}{2 \times 25}\\\\F=1269 \;\rm N[/tex]
Thus, the required magnitude of the average force exerted on the car is 1269 N.
Learn more about the Newton's second law of motion here:
https://brainly.com/question/19860811
