The position of a paddle on a waterwheel after t seconds is modeled by f(t) = 5.25 cosine (StartFraction pi Over 16 EndFraction t minus pi). A positive function value indicates the paddle is above the waterline, while a negative value indicates the paddle is below the waterline.

What is the initial position of the paddle?

10.5 ft above the waterline
5.25 ft above the waterline
0 ft at the waterline
5.25 ft below the waterline

The position of a paddle on a waterwheel after t seconds is modeled by ft 525 cosine StartFraction pi Over 16 EndFraction t minus pi A positive function value i class=

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Answer:

5.25ft Below the waterline

Step-by-step explanation:

1. So basically I put this equation into a graphing calculator (I use Desmos) and replaced "t" with "x" cuz computers are weird.

2. Then it pops up a graph. We need to know the initial position of the paddle. This means where is the paddle when no time has passed, aka the y-intercept. I look and it's at -5.25, meaning 5.25 below the waterline.

This question is based on the concept of graph. Therefore, the correct option is D that is 5.25 ft below the waterline.

Given:

The position of a paddle on a waterwheel after t seconds is modeled by

[tex]f(x)=5.25 \;\cos(\dfrac{\pi }{16} t-\pi )[/tex]

We need to determine the initial position of paddle.

By using graph, we obtain the initial position of paddle.

As graph is attached below,

From the graph, it is  observe that,

Taking  time in (t seconds) on x- axis, and on y-axis, position of paddle

(in feet).

Now plot the graph of the given equation i.e.

[tex]f(x)=5.25 \;\cos(\dfrac{\pi }{16} t-\pi )[/tex]

As from the graph it show that , when no time is passed i.e. x - intercept is 0.Therefore, the position of paddle is -5.25 i.e. 5.25 ft below the waterline.

Therefore, the correct option is D that is 5.25 ft below the waterline.

For further details, please prefer this link :

https://brainly.com/question/17267403

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