Answer:
5. 200/1 = 200 ft/min
6. 600/3 = 200 ft/min
Step-by-step explanation:
5. The rate of change of a graph is the ratio of vertical change to horizontal change. You are asked to find the rate of change from 1 minute to 2 minutes, so you want to find the distance (ft) at 2 minutes and at 1 minute.
Reading the graph, you see that at 2 minutes, the distance is 400 ft. At 1 minute, it is 200 ft.
So, the ratio of the two differences is ...
change in distance / change in time
[tex]=\dfrac{400-200}{2-1}=\dfrac{200}{1}=200\quad\text{ft per min}[/tex]
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6. Using the same idea, we want to use the graph values at 4 minutes and 1 minute.
[tex]\dfrac{\text{$\Delta$distance}}{\text{$\Delta$time}}=\dfrac{800-200}{4-1}=\dfrac{600}{3}=200\quad\text{ft per min}[/tex]
