Question

A pelican flying along a horizontal path drops

a fish from a height of 5.0 m. The fish travels

8.9 m horizontally before it hits the water

below.

What was the pelican’s initial speed? The

acceleration of gravity is 9.81 m/s

(I GOT 8.734 ,/s which was CORRECT. now I am stuck on part 2).

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PART 2: If the pelican was traveling at the same speed

but was only 1.9 m above the water, how

far would the fish travel horizontally before

hitting the water below?

Answer in units of m.
(Numbers must not be rounded during the problem and the answer has to include 4 decimal places after such as 1.2345) Thx!

Answer 1

Answer:

The initial speed of the pelican is 8.81 m/s.

Explanation:

Given;

height of the pelican, h = 5.0 m

horizontal distance, X = 8.9 m

The time of flight is given by;

$t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2*5}{9.81} } \\\\t = 1.01 \ s$

The initial horizontal speed of the pelican is given by;

X = vₓt

vₓ = X / t

vₓ = 8.9 / 1.01

vₓ = 8.81 m/s

Therefore, the initial speed of the pelican is 8.81 m/s.