"2.5 mL" of the suspension are required.
According to the question,
= [tex]0.125\times 1000[/tex]
= [tex]125 \ mg[/tex]
Now,
125 mg present in (Suspension required):
= [tex](\frac{5.0}{250}\times 125 )[/tex]
= [tex]2.5 \ mL[/tex]
Thus the above approach is correct.
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