Question

The length of Marshall's rectangular poster is 2 times its width. If the perimeter is 24 inches, what is the area of the poster?

Answer 1

Length=2x
width=x
Perimeter of a rectangle=2(length) + 2(width)
We can suggest this equation:
24=2(2x)+2x
24=4x+2x
24=6x
x=24/6
x=4

length=2x=2(4)=8
width=x=4

area of a rectangle=length x width
area of this poster (rectangle)=(8 in)( 4 in)=32 in².

The area of this poster will be: 32 in²

Answer 2

Area of Marshall's rectangular poster is 27 inches²

Give that;

Length of poster = 3[Width of poster]

Perimeter of poster = 24 inches

Find:

Area of Marshall's rectangular poster

Computation:

Assume;

Width of poster = a

Length of poster = 3a

Perimeter of rectangle = 2[l + b]

24 = 2[3a + a]

24 = 2[4a]

8a = 24

a = 24 / 8

a = 3

Width of poster = 3 inches

Length of poster = 3a

Length of poster = 3(3)

Length of poster = 9 inches

Area of rectangle = [l][b]

Area of Marshall's rectangular poster = [3][9]

Area of Marshall's rectangular poster = 27 inches²

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