Question

What is the midpoint of segment EF? E(-8,1) and F(1,1

Answer 1

Answer:

The answer is

$( - \frac{7}{2} \: , \: 1)$

Step-by-step explanation:

The midpoint M of two endpoints of a line segment can be found by using the formula

$M = ( \frac{x1 + x2}{2} , \: \frac{y1 + y2}{2} )$

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

E(-8,1) and F(1,1)

The midpoint is

$M = ( \frac{ - 8 + 1}{2} \: , \: \frac{1 + 1}{2} ) \\ = ( - \frac{7}{2} \: , \: \frac{2}{2} )$

We have the final answer as

$( - \frac{7}{2} \: , \: 1)$

Hope this helps you

Answer 2

Step-by-step explanation:

Hey there!

The given points are; (-8,1) and F (1,1). Let M(x,y) be the midpoints.

Now,

Using midpoint formulae.

$(x,y) = ( \frac{x1 + x2}{2} , \frac{y1 + y2}{2} )$

Put all values.

$(x,y) =( \frac{ - 8 + 1}{2} , \frac{1 + 1}{2} )$

Simplify it to get answer.

$(x,y) = ( \frac{ - 7}{2} , \frac{2}{2})$

$(x,y) = (\frac{ - 7}{2} ,1)$

Therefore the slope is M(-7/2,1).

Hope it helps...